2019 Neco Gce Physics Obj And Theory Answers

Sponsored Ads

1-10: CACABDBECA
11-20: CCDBBDEECA
21-30: ECACEDACDB
31-40: CADBBDCBBC
41-50: EBCADACDAE
51-60: CDCBCEDCCB

(4a)
(i) Nuclear fission
(ii) Discharge of fossil fuels such as oil, gas and coal to the atmosphere

(4b)
h = 1.6m
V = ?
g = 10m/s²
V² = u²+2gh
V² = 2×10×1.8
V² = 36m/s
V = √36
= 6m/s

(12ai)
The volume of a stone is measured using a measuring cylinder by firstly measuring the volume of water in cylinder (v2) , then the stone is dropped into the cylinder (v2)
Let v1 = volume of water without stone
V2 = volume of water and stone.
Therefore the volume of stone = v2 – v1

(12aii)
(i) Nature of the liquid.
(ii) Volume of the liquid.
(iii) Shape of the container of the liquid.

(12bi)
A body is said to be on dynamic equilibrium if the body is moving continually with a constant acceleration.

(12bii)
Draw the diagram [https://i.imgur.com/6KYI8Ca.jpg]

Fy = 0(at equilibrium)
Fa + Fb – W1 – W2 = 0
Fb = W1+W2-Fa ….(1)
Taking moment about point A
W1 × 0.02 + W2×0.05 – Fb×0.07 = 0
0.07Fb = 0.02W1 + 0.05W2
Fb = 2W1+5W2/7 …(2)

Check Also  2019 Neco Gce Biology Practical Answers

(12ci)
Draw the diagram [https://i.imgur.com/6KYI8Ca.jpg]u = 7m/s
Time of flight = 10s

Time of flight (T) = 2usinΦ/g
10 = 2×70sinΦ/10
140sinΦ = 100
sinΦ = 100/140 = 0.7143
Φ = sin-¹(0.7143)
Φ = 45.58°
Φ = 46°

(12cii)
Maximum height = u²sin²Φ/g
H = 70²sin²45.58/2×10
H = 4900×0.7143²/20
H = 125m
Maximum height = 125m

(15a)
The charge on a body can be identified using a gold leaf electroscope as follows:
By touching the body to the brass disc: Let the electroscope be charged with positive charge. The leaves will be in diverged position. The body to be tested is touched with the brass disc of the electroscope and the divergence of leaves is observed.

Case (i): If the leaves diverge more, the body is positively uncharged. When the body touches the electroscope, its charges are transferred to the leaves. There is an increase in repulsion which happens due to increase in the same kind of charge, and hence, this indicates that the body is positively charged.

Check Also  2019 Neco Gce English Language Obj, Theory And Test Of Orals Answers

Case (ii): If the divergence of the leaves decreases, the body is negatively charged. When the body touches the electroscope, its charges are transferred to the leaves. There is a decrease in repulsion which happens due to decrease in the same kind of charge or increase in opposite kind of charge, and hence, this indicates that the body is negatively charged.

(15b)
F = Gm₁m₂/r²
F = mg

If m₁ = m₂
Gm₁m₂/r² = mg
.:. g = Gm/r

(15c)
R1 = 2ohms
R2 = 3ohms
First connected in parallel
1/RT = 1/2 + 1/3
1/RT = 3+2/6
1/RT = 5/6
5RT = 6
RT = 6/5
RT = 6/5ohms

To a 120v
V = IR
I = 120/6/5
I = 120÷6/5
I = 120 × 5/6
I = 100A

But when connected in series
RT = R1 + R2
RT = 2 + 3
RT = 5ohms

Check Also  2019 Neco Gce Geography Theory Answers

To a 120v
V = IR
I = V/R
I = 120/5
I = 24A
So the difference between the two arrangement in current
[100 – 24]A
= 76A

JOIN SERIEZLOADED.COM.NG TODAY!!!

Promote your Music's /Videos on Seriezloaded, WhatsApp 08077722280 or Send a Mail To music@seriezloaded.com.ng

About SL EXaM BOSS 23 Articles
For any Exam Matters, WhatsApp 09060942377.

Be the first to comment

Leave a Reply